B\u00ed Quy\u1ebft Th\u1eafng K\u00e8o VAR: Ph\u00e2n T\u00edch v\u00e0 Chi\u1ebfn L\u01b0\u1ee3c Chuy\u00ean Nghi\u1ec7p<\/a><\/strong><\/p><\/blockquote>\nC\u00e1c t\u1ef7 l\u1ec7 ch\u1ea5p k\u00e8o tr\u00ean k\u00e8o d\u01b0\u1edbi ph\u1ed5 bi\u1ebfn<\/b><\/h2>\n
\u0110\u1ec3 hi\u1ec3u s\u00e2u h\u01a1n v\u1ec1 th\u1ebf gi\u1edbi c\u00e1 \u0111\u1ed9 b\u00f3ng \u0111\u00e1, ch\u00fang ta s\u1ebd kh\u00e1m ph\u00e1 <\/span>c\u00e1c t\u1ef7 l\u1ec7 ch\u1ea5p trong k\u00e8o tr\u00ean k\u00e8o d\u01b0\u1edbi<\/b>. L\u1ef1a ch\u1ecdn k\u00e8o ph\u00f9 h\u1ee3p \u0111\u00f2i h\u1ecfi s\u1ef1 quan s\u00e1t k\u1ef9 l\u01b0\u1ee1ng, d\u01b0\u1edbi \u0111\u00e2y l\u00e0 nh\u1eefng lo\u1ea1i t\u1ef7 l\u1ec7 ch\u1ea5p b\u1ea1n c\u1ea7n bi\u1ebft:<\/span><\/p>\nCh\u1ea5p 1\/2 tr\u00e1i (0.5 tr\u00e1i)<\/b><\/h3>\n
\u0110\u00e2y l\u00e0 m\u1ed9t ph\u01b0\u01a1ng th\u1ee9c c\u01b0\u1ee3c th\u00f4ng d\u1ee5ng. Khi b\u1ea1n ch\u1ecdn “k\u00e8o tr\u00ean”, \u0111\u1ed9i n\u00e0y s\u1ebd ch\u1ea5p “k\u00e8o d\u01b0\u1edbi” n\u1eeda b\u00e0n. N\u1ebfu tr\u1eadn \u0111\u1ea5u k\u1ebft th\u00fac v\u1edbi t\u1ef7 s\u1ed1 h\u00f2a, nh\u1eefng ng\u01b0\u1eddi \u0111\u00e3 c\u01b0\u1ee3c cho “k\u00e8o tr\u00ean” s\u1ebd m\u1ea5t c\u01b0\u1ee3c. \u0110i\u1ec1u n\u00e0y x\u1ea3y ra v\u00ec “k\u00e8o d\u01b0\u1edbi” nh\u1eadn th\u00eam n\u1eeda \u0111i\u1ec3m, t\u1ea1o ra l\u1ee3i th\u1ebf cho h\u1ecd.<\/span><\/p>\nCh\u1ea5p 1\/4 tr\u00e1i (0.25 tr\u00e1i)<\/b><\/h3>\n
T\u01b0\u01a1ng t\u1ef1 ch\u1ea5p n\u1eeda tr\u00e1i nh\u01b0ng v\u1edbi m\u1ed9t s\u1ef1 kh\u00e1c bi\u1ec7t nh\u1ecf. Trong tr\u01b0\u1eddng h\u1ee3p tr\u1eadn \u0111\u1ea5u k\u1ebft th\u00fac h\u00f2a, “k\u00e8o d\u01b0\u1edbi” ch\u1ec9 nh\u1eadn m\u1ed9t n\u1eeda s\u1ed1 ti\u1ec1n c\u01b0\u1ee3c c\u1ee7a h\u1ecd, kh\u00f4ng gi\u1ed1ng nh\u01b0 ch\u1ea5p n\u1eeda tr\u00e1i n\u01a1i h\u1ecd th\u1eafng c\u1ea3 c\u01b0\u1ee3c.<\/span><\/p>\n